0.4x^2+2x+2=45

Solution for 0.4x^2+2x+2=45 equation:

0.4x^2+2x+2=45

We move all terms to the left:

0.4x^2+2x+2-(45)=0

We add all the numbers together, and all the variables

0.4x^2+2x-43=0

a = 0.4; b = 2; c = -43;
Δ = b2-4ac
Δ = 22-4·0.4·(-43)
Δ = 72.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{72.8}}{2*0.4}=\frac{-2-\sqrt{72.8}}{0.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{72.8}}{2*0.4}=\frac{-2+\sqrt{72.8}}{0.8}
$